#### Answer

$(x,y,z) = (4,1,-3)+n(1,2,3)$

#### Work Step by Step

In general we can write an equation for a line in this form:
$(x,y,z) = (a,b,c)+n(a',b',c')$
where $(a,b,c)$ is a point on the line and $(a',b',c')$ is a direction vector
$(4,1,-3)$ is a point on the line
$(1,2,3)$ is a direction vector
We can write an equation for this line:
$(x,y,z) = (4,1,-3)+n(1,2,3)$