Answer
$$\left[\begin{array}{r}{1}&{-2}&{3} \\ {2}&{1}&{-5} \end{array}\right]\left[\begin{array}{r}{x_1} \\ {x_2}\\{x_3} \end{array}\right]=\left[\begin{array}{r}{0} \\ {4} \end{array}\right]$$
Work Step by Step
The system $$
\begin{aligned} x_{1}-2 x_{2}+3 x_{3} &=0 \\ 2 x_{1}+x_{2}-5 x_{3} &=4 \end{aligned}
$$
cam written in the form
$Ax=b$, as follows
$$\left[\begin{array}{r}{1}&{-2}&{3} \\ {2}&{1}&{-5} \end{array}\right]\left[\begin{array}{r}{x_1} \\ {x_2}\\{x_3} \end{array}\right]=\left[\begin{array}{r}{0} \\ {4} \end{array}\right].$$
