## Linear Algebra: A Modern Introduction

Published by Cengage Learning

# Chapter 1 - Vectors - 1.1 The Geometry and Algebra of Vectors - Exercises 1.1 - Page 17: 44

#### Answer

$x=4$

#### Work Step by Step

Since $4+3=7$ in $\mathbb{Z}$, and $7$ divided by $5$ leaves a remainder of $2$, $4+3=2$ in $\mathbb{Z}_5$. Thus, by inspection, there is a solution to the equation $x+3=2$.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.