Linear Algebra: A Modern Introduction

Published by Cengage Learning
ISBN 10: 1285463242
ISBN 13: 978-1-28546-324-7

Chapter 1 - Vectors - 1.1 The Geometry and Algebra of Vectors - Exercises 1.1: 15

Answer

$$5a$$

Work Step by Step

We're given the expression $$2(a-3b) + 3(2b+a)$$ By the distributive property of scalar multiplication over vector addition (Theorem 1.1.e), we get: $$2a+2(-3)b + 3(2b)+3a$$ By the associative property of scalar-vector multiplication (Theorem 1.1.g), we get: $$2a-6b + 6b+3a$$ Using the commutativity (Theorem 1.1.a) and associativity (Theorem 1.1.b) of vector addition, we rearrange to get: $$(2a+3a) + (-6b + 6b)$$ By applying the distributive property of vector-scalar multiplication over scalar addition (Theorem 1.1.f), we get: $$(2+3)a + (-6+6)b$$ With scalar addition, we condense to: $$5a + 0b$$ And by the identity property of vector addition (Theorem 1.1.c), we get $$5a$$
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