Answer
$y^2=-2 \sec x+c $
Work Step by Step
Given: $y \cos^2 x dy=-\sin x dx$
Separate the differentials and integrate.
$\int y dy=-\int \sec x \tan x dx$
This implies that $\dfrac{y^2}{2}=-\sec x+c$
Thus, $y^2=-2 \sec x+c $
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 7 - Practice Exercises - Page 421: 30
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