University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 7 - Practice Exercises - Page 421: 23


$\ln 5-\ln 3=\ln \frac{5}{3}$

Work Step by Step

Here, $f(x)=\ln (5x)$ and $g(x)=\ln (3x)$ Now, $|f(x)-g(x)|=|(\ln x+\ln 5)-(\ln x+\ln 3)|$ Thus, $|f(x)-g(x)|=\ln 5-\ln 3$
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