University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 7 - Practice Exercises - Page 421: 25



Work Step by Step

Here, $\dfrac{\log_4(x)}{\log_2(x)}=\dfrac{\frac{\ln x}{\ln 4}}{\frac{\ln x}{\ln 2}}$ This implies that $\dfrac{\log_4(x)}{\log_2(x)}=\dfrac{\ln 2}{\ln 2^2}$ or, $\dfrac{\ln 2}{2 \ln (2)}=\dfrac{1}{2}$
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