Answer
$\dfrac{1}{2}$
Work Step by Step
Here, $\dfrac{\log_4(x)}{\log_2(x)}=\dfrac{\frac{\ln x}{\ln 4}}{\frac{\ln x}{\ln 2}}$
This implies that $\dfrac{\log_4(x)}{\log_2(x)}=\dfrac{\ln 2}{\ln 2^2}$
or, $\dfrac{\ln 2}{2 \ln (2)}=\dfrac{1}{2}$