University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.1 - Area and Estimating with Finite Sums - Exercises - Page 292: 16

Answer

$\frac{25}{96}\approx 0.2604$

Work Step by Step

Given-$ƒ(x) = \frac{1}{x}$ on the interval $[1, 9]$ Now, using a finite sum, we can partition the interval into four subintervals of equal length and evaluate ƒ at the subinterval midpoints. The length of each subinterval can be calculated as follows: Length of subinterval = $\frac{\text{upper bound} - \text{lower bound}}{\text{number of subintervals}}$ = $\frac{(9 - 1)}{4}$ = $2$ Now, we can calculate the subinterval midpoints: Subinterval $1$: midpoint = $\frac{(1 + 3)}{2}= 2$ Subinterval $2$: midpoint = $\frac{(3 + 5) }{2}= 4$ Subinterval $3$: midpoint = $\frac{(5 + 7) }{2}= 6$ Subinterval $4$: midpoint = $\frac{(7 + 9) }{2}= 8$ Next, we evaluate ƒ at these subinterval midpoints: $ƒ(2) = \frac{1}{2}$ $ƒ(4) = \frac{1}{4}$ $ƒ(6) = \frac{1}{6}$ $ƒ(8) = \frac{1}{8}$ Finally, we can calculate the average value of ƒ on the interval [1, 9] using the finite sum: Average value of ƒ = $\frac{\text{sum of function values}}{\text{number of subintervals}}$ = $\frac{\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+\frac{1}{8}}{4}$ ≈ $\frac{25}{96}$ ≈ $0.2604$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.