University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.1 - Area and Estimating with Finite Sums - Exercises - Page 292: 14

Answer

a) $240$ ft/sec. b) $1600$ ft

Work Step by Step

a). Using the formula for velocity, we have: Velocity = Initial velocity - (acceleration due to gravity $\times$ time) Velocity = $400$ ft/sec - ($32 ft/sec^{2}$ $\times 5$ sec) Velocity = $400$ ft/sec - $160$ ft/sec Velocity = $240$ ft/sec b). Displacement = Initial velocity $\times$ time - (1/2) $\times$ acceleration $\times$ time$^{2}$ Displacement = $400 \times 5 - (1/2) \times 32 \times (5^{2})$ Displacement = $2000 - (1/2) \times 32 \times 25$ Displacement = $2000 - 16 \times 25$ Displacement = $2000 - 400$ Displacement = $1600$ ft.
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