University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.3 - Monotonic Functions and the First Derivative Test - Exercises - Page 228: 7

Answer

$ a.\quad$ critical points at $x=-2,0,1$ $ b.\quad$ increasing on $(-\infty,-2)\cup(1, \infty)$, decreasing on $(-2,0)\cup(0,1)$. $ c.\quad$ local minimum at $x=1$

Work Step by Step

$(a)$ $f'$ is defined everywhere except at $ x=-2\qquad$ ... critical point $f'(x)=0$ for $ x=0,1\qquad$ ... critical points Critical points at $x=-2,0,1$ $(b)$ $\left[\begin{array}{lllll} & (-\infty,-2) & (-2,0) & (0,1) & (1,\infty)\\ \text{test point} & -3 & -1 & 0.5 & 2\\ \text{evaluate }f' & 36 & -2 & -0.05 & 1\\ \text{sign of }f' & + & - & - & +\\ \text{behavior of }f(x) & \nearrow^{...} & {}^{...}\searrow & \searrow & \nearrow \end{array}\right]$ (the "$\nearrow^{... },\ {}^{...}\searrow$" indicate that $f'$ is undefined at the border.) f is increasing on $(-\infty,-2)\cup(1, \infty)$, decreasing on $(-2,0)\cup(0,1)$. $(c)$ From the table, we see that f has: a local minimum at $x=1$,
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