Chapter 4 - Section 4.2 - The Mean Value Theorem - Exercises - Page 224: 53

See below.

Let us consider that $s(t)$ denotes the distance covered by the trucker at time $t$. Then, we have $s(0)=0$ and $s(24)=184$ Let us apply The Mean Value Theorem to find the velocity at time $t$ such that $|v(t)|=|s'(t)|=|\dfrac{f(b)-f(a)}{b-a}|=|\dfrac{s(24)-s(0)}{24-0}|=\dfrac{184}{24}=7\dfrac{2}{3}$, which is greater than $7.5$