Answer
$s(t)=e^t+19t+4$
Work Step by Step
Here, $a=e^t; v(0)=20;s(0)=5$
Since the derivative of velocity is acceleration, $v(t)=e^t+C$
Therefore, $v(0)=20$ Then $20=e^0+C \implies C=19$
Thus, $v(t)=e^t+19$
Since, the derivative of position (that is, $s(t)$) is velocity, $s(t)=e^t+19t+C'$
Therefore, $s(0)=5$ Then $5=e^0+19(0)+C' \implies C'=4$
Hence, $s(t)=e^t+19t+4$