## University Calculus: Early Transcendentals (3rd Edition)

Let us consider that $s(t)$ denotes the distance covered by the trucker at time $t$. Then, we have $s(0)=0$ and $s(2)=159$ Let us apply The Mean Value Theorem to find the velocity at time $t$ such that $|v(t)|=|s'(t)|=|\dfrac{f(b)-f(a)}{b-a}|=|\dfrac{s(2)-s(0)}{2-0}|=\dfrac{159}{2}=79.5$, which is greater than $65$