Chapter 3 - Section 3.3 - Differentiation Rules - Exercises - Page 136: 44

$y' = 24x^{2} - 16x^{3} +6 -6x$ $y'' = 48x - 48x^{2} -6$ $y''' = 48- 96x$ $y'''' = -96$ $y''''' = 0$ (and all higher derivatives will also be 0)

$y = (4x^{2}+3)(2-x)x$ $y = (4x^{2}+3)(2x - x^{2})$ $y = 8x^{3} - 4x^{4}+6x -3x^{2}$ $y' = 24x^{2} - 16x^{3} +6 -6x$ $y'' = 48x - 48x^{2} -6$ $y''' = 48- 96x$ $y'''' = -96$ $y''''' = 0$ (and all higher derivatives will also be 0)