Answer
$y' = \frac{2}{7}x^{-\frac{5}{7}} + ex^{e-1}$
Work Step by Step
$y =\sqrt[7]( x^{2}) + x^{e}$
$y = x^{\frac{2}{7}} + x^{e}$
$y' = \frac{2}{7}x^{-\frac{5}{7}} + ex^{e-1}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 3 - Section 3.3 - Differentiation Rules - Exercises - Page 136: 37
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