University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.3 - Differentiation Rules - Exercises - Page 136: 39

Answer

$\displaystyle r' = \frac{e^{s}(s-1)}{s^{2}}$

Work Step by Step

$r = \frac{e^{s}}{s}$ $r' = \frac{s(e^{s}) - e^{s}(1)}{s^{2}}$ $r' = \frac{e^{s}(s-1)}{s^{2}}$
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