Answer
a) $0.08\pi\ m^2$
b) 2%
Work Step by Step
Area of a circle: $A=\pi r^2$
differentiating the above:
$dA=2\pi r dr$
radius r =2.00m
change in radius(dr)= final radius - initial radius = $2.02-2.00=.02m$
so $dA=2\pi\ 2\times.02=0.08\pi$
$%change in Area = \frac{dA}{\pi r^2}\times100=\frac{0.08\times100}{\pi\times2^2}=2%$