Answer
a) 0.231
b) 0.2
c) 0.031
Work Step by Step
We are given: $f(x)=x^3-x$
$\delta f=f(1+0.1)-f(1)$
or $\delta f=f(1.1)-f(1)=0.231-0=0.231$
or $\delta f=0.231$
differentiation of f(x):
$f'(x)=3x^2-1$
$df=f'(1)\times0.1$
$df=(3-1)\times0.1=0.2$
$df=0.2$
so
$|\delta f-df|=|0.231-0.2|=|0.031|=0.031$
Thus the final answer is: a)0.231, b)0.2, c)0.031