University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.11 - Linearization and Differentials - Exercises - Page 199: 49


$dV=2\pi rhdr$

Work Step by Step

We are given: $V=\pi r^2h$ on differentiating both sides: $dV=\pi\times (2rhdr+r^2dh)$ $dh=0$ (as height does not change) $dV=2\pi rhdr$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.