University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.11 - Linearization and Differentials - Exercises - Page 199: 50


$dV=2\pi rdh$

Work Step by Step

We are given: $S=2\pi rh$ on differentiating both sides: $dS=2\pi\times (hdr+rdh)$ $dr=0$ (as radius does not change) $dV=2\pi rdh$
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