Answer
$dV=2\pi rdh$
Work Step by Step
We are given: $S=2\pi rh$
on differentiating both sides:
$dS=2\pi\times (hdr+rdh)$
$dr=0$ (as radius does not change)
$dV=2\pi rdh$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 3 - Section 3.11 - Linearization and Differentials - Exercises - Page 199: 50
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