University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.11 - Linearization and Differentials - Exercises - Page 198: 20

Answer

${dy}=(\sqrt{(1-x^2})-\frac{x^2}{\sqrt{ ({1-x^2})}}){dx}$

Work Step by Step

We evaluate the function: $y=x\sqrt{(1-x^2)}$ on differentiating the above: $\frac{dy}{dx}=\frac{d(x\sqrt{(1-x^2)}}{dx}$ or ${dy}=(\sqrt{(1-x^2})-\frac{x^2}{\sqrt{ ({1-x^2})}}){dx}$ The final answer is: ${dy}=(\sqrt{(1-x^2})-\frac{x^2}{\sqrt{ ({1-x^2})}}){dx}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.