Answer
$dy=(3x^2-\frac{3}{2\sqrt {x}}){dx}$
Work Step by Step
We evaluate the function $y=x^3-3\sqrt{x}$
on differentiating the above:
$\frac{dy}{dx}=\frac{d(x^3-3\sqrt {x})}{dx}$
or $\frac{dy}{dx}=3x^2-\frac{3}{2\sqrt {x}}$
or $dy=(3x^2-\frac{3}{2\sqrt {x}}){dx}$
The final answer is: $dy=(3x^2-\frac{3}{2\sqrt {x}}){dx}$
