## University Calculus: Early Transcendentals (3rd Edition)

$L(x)=10x-13$
Given: $f(x)=x^3-2x+3$ L(x)=f(a)+f'(a)(x-a) $f'(x)=3x^2-2$ a=2 $f(2)=2^3-2\times2+3=7$ $f'(2)=3\times2^2-2=10$ then $L(x)=7+10(x-2)$ $L(x)=7+10x-20=10x-13$ $L(x)=10x-13$ Thus, the final answer: $L(x)=10x-13$