University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 16 - Section 16.2 - First-Order Linear Equations - Exercises - Page 16-14: 23

Answer

(a) is incorrect and (b) is correct.

Work Step by Step

Here, we have $x \int \ln |x| dx=x(\ln |x|+c$ or, $x \int \ln |x| dx=x\ln |x|+cx$ Thus, it can be seen that solution (a) is incorrect because here the arbitrary constant depends on the values of $c$ but solution (b) is correct because it is the same as the solution. Hence, (a) is incorrect and (b) is correct.
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