University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 15 - Section 15.1 - Line Integrals - Exercises - Page 826: 5

Answer

$\bf {Graph(d)}$

Work Step by Step

Since, we have $r(t)=ti+t j+t k$ This shows us that any point on the graph has the form of $(t,t,t)$ . Thus, this is a line passing through the origin containing the point $(2,2,2)$. Hence, the required answer is $\bf {Graph(d)}$
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