Answer
$\bf {Graph(c)}$
Work Step by Step
Since, we have $x=t,y=1-t, z=0$
Thus, $x+y=1$ and $z=0$
This shows a line segment joining $(1,0,0),(0,1,0)$ and so, the x and y intercepts are both $1$.
Hence, the required answer is $\bf {Graph(c)}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 15 - Section 15.1 - Line Integrals - Exercises - Page 826: 1
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