#### Answer

$\bf {Graph(e)}$

#### Work Step by Step

Since, we have $r(t)=i+j+t k$
This shows us that any point on the graph has the form of $(1,1,t)$ . Thus, the x and y intercepts are both $1$ and z-varies from $-1$ to $+1$
Hence, the required answer is $\bf {Graph(e)}$