University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 15 - Section 15.1 - Line Integrals - Exercises - Page 826: 4

Answer

$\bf {Graph(a)}$

Work Step by Step

Since, we have $r(t)=ti$ and $-1 \lt t \lt 1$ This shows us that any point on the graph has the form of $(t,0,0)$ . Thus, the y and z intercepts are both $0$ and x-varies from $-1$ to $+1$, which makes a line segment along the $x$-axis. Hence, the required answer is $\bf {Graph(a)}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.