University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 13 - Section 13.1 - Functions of Several Variables - Exercises - Page 682: 4

Answer

$a.\quad 7$ $b.\quad 0$ $c.\quad\sqrt{35}$ $d.\quad\sqrt{\dfrac{21}{2}}$

Work Step by Step

$ a.\quad$ $f(0, 0,0)=\sqrt{49-0-0-0}=7$ $ b.\quad$ $f(2, -3,6)=\sqrt{49-4-9-36}=0$ $ c.\quad$ $f(-1,2,3)=\sqrt{49-1-4-9}=\sqrt{35}$ $ d.\quad$ $f(\displaystyle \frac{4}{\sqrt{2}}, \frac{5}{\sqrt{2}}, \frac{6}{\sqrt{2}})=\sqrt{49-\frac{16}{2}-\frac{25}{2}-\frac{36}{2}}=\sqrt{\frac{98-77}{2}}=\sqrt{\frac{21}{2}}$
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