Answer
(a)$f(0,0) = 0$
(b)$f(-1,1) = 0$
(c) $f(2,3) = 58$
(d) $f(-3,-2) = 33$
Work Step by Step
- Substitute the values of "x" and "y" by the given ones in each point:
$f(x,y) = x^2 + xy^3$
(a) $f(0,0)$
$f(0,0) = 0^2 + 0*0^3 = 0$
(b) $f(-1,1)$
$f(-1,1) = (-1)^2 + (-1)(1)^3 = 1 + (-1)*(1) = 1 -1 = 0$
(c) $f(2,3)$
$f(2,3) = (2)^2 + (2)(3)^3 = 4 + (2)(27) = 4 + 54 = 58$
(d) $f(-3,-2)$
$f(-3,-2) = (-3)^2 + (-3)(-2)^3 = 9 + (-3)(-8) = 9 + 24 = 33$
