Answer
(a) $f(2,\frac{\pi}{6}) = \frac{\sqrt {3}}{2}$
(b) $f(-3, \pi/12) = -\frac{\sqrt{2}}{2}$
(c) $f(\pi, \frac{1}{4}) = \frac{\sqrt 2}{2}$
(d) $f(-\frac{\pi}{2},-7) = -1$
Work Step by Step
- Substitute the values of "x" and "y" by the given ones in each point:
$f(x,y) = sin(xy)$
(a)
$f(2,\frac{\pi}{6}) = sin(2 * \frac{\pi}{6}) = sin (\frac{\pi}{3}) = \frac{\sqrt {3}}{2}$
(b)
$f(-3, \pi/12) = sin(-3 * \frac{\pi}{12}) = sin (-\frac{\pi}{4}) = -\frac{\sqrt{2}}{2}$
(c)
$f(\pi, \frac{1}{4}) = sin(\pi *\frac{1}{4}) = sin(\frac{\pi}{4}) = \frac{\sqrt 2}{2}$
(d)
$f(-\frac{\pi}{2},-7) = sin(-\frac{\pi}{2}*(-7)) = sin(\frac{7\pi}{2}) = sin(\frac{3\pi}{2}) = -1$
