University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 13 - Section 13.1 - Functions of Several Variables - Exercises - Page 682: 3

Answer

$a.\displaystyle \quad\frac{4}{5}$ $b.\displaystyle \quad\frac{8}{5}$ $c.\quad 3$ $d.\quad 0$

Work Step by Step

$ a.\quad$ $f(3, -1,2)=\displaystyle \frac{3-(-1)}{(-1)^{2}+(2)^{2}}=\frac{4}{5}$ $ b.\quad$ $f(1, \displaystyle \frac{1}{2}, -\frac{1}{4})=\frac{1-(\frac{1}{2})}{(\frac{1}{2})^{2}+(-\frac{1}{4})^{2}}=\frac{8}{5}$ $ c.\quad$ $f(0, -\displaystyle \frac{1}{3},0)=\frac{0-(-\frac{1}{3})}{(-\frac{1}{3})^{2}+(0)^{2}}=3$ $ d.\quad$ $f(2,2,100)=\displaystyle \frac{2-(2)}{(2)^{2}+(100)^{2}}=0$
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