University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 13 - Practice Exercises - Page 750: 49

Answer

$2y-z=2$

Work Step by Step

The vector equation can be calculated as:$\nabla f(r_0) \cdot (r-r_0)=0$ The equation of the tangent for $\nabla f( 0,1,0)=\lt 0,2,-1 \gt$ is: $0+2(y-1)-1(z-0)=0$ or, $2y-2-z=0 \implies 2y-z=2$ Hence, $2y-z=2$
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