Answer
$$f_{xx}=0; \\f_{yy}=2- \cos \ y+7e^{y} ;\\f_{xy}=f_{yx}=-3$$
Work Step by Step
$$f_{x}=-3y;\\f_{xx}=0;\\f_{yx}=-3;\\f_{y}=2y-3x-\sin \ y+7e^{y}$$
The second partial derivatives are as follows:
$$f_{xx}=0; \\f_{yy}=2- \cos \ y+7e^{y} ;\\f_{xy}=f_{yx}=-3$$
