University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 1 - Section 1.6 - Inverse Functions and Logarithms - Exercises - Page 50: 79


The third solution would be $-0.767$.

Work Step by Step

Looking at the graph, besides $(2,4)$ and $(4,6)$ as points of intersection between 2 graphs, there is another one, which is $(-0.767,0.588)$ Therefore, the third solution would be $-0.767$.
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