Answer
$$t=(x+1)^2$$
Work Step by Step
$$e^{(x^2)}e^{(2x+1)}=e^t$$ $$e^{x^2+2x+1}=e^t$$
- Recall that as $e^x=e^a$, then $x=a$
So here we have: $$t=x^2+2x+1$$ $$t=(x+1)^2$$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 1 - Section 1.6 - Inverse Functions and Logarithms - Exercises - Page 50: 60
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