## University Calculus: Early Transcendentals (3rd Edition)

$$t=(x+1)^2$$
$$e^{(x^2)}e^{(2x+1)}=e^t$$ $$e^{x^2+2x+1}=e^t$$ - Recall that as $e^x=e^a$, then $x=a$ So here we have: $$t=x^2+2x+1$$ $$t=(x+1)^2$$