University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 1 - Section 1.1 - Functions and Their Graphs - Exercises: 49

Answer

Even.

Work Step by Step

Even functions are, where f(-x)=f(x), here $f(x)=x^{2}+1$, $f(-x)=(-x)^{2}+1=x^{2}+1$, which are equal, threfore the function is even.
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