## University Calculus: Early Transcendentals (3rd Edition)

a) $y=x\ \$ on $\ \ [0,1]$ $y=-x+2\ \$ on $\ \ (1,2]$ b) $y=2\ \$ on $\ [0,1)$ and $\ [2,3)$ $y=0\ \$ on $\ [1,2)$ and $\ [3,4]$
$a)$ Find the equation of line that goes through the points $\ (0,0)\ \ \mathrm{and}\ \ (1,1)\$ and the line that goes through $\ (1,1)\ \ \mathrm{and}\ \ (2,0).$ Secondly, write down the domain restrictions. $y-0=\frac{1-0}{1-0}(x-0)$ $y=x\ \$ on $\ \ [0,1]$ $y-1=\frac{0-1}{2-1}(x-1)$ $y=-x+2\ \$ on $\ \ (1,2]$ $b)$ We can see that the upper parts in the graph are represented with the function $\ y=2\$ and lower parts with the function $\ y=0.$ We just need to apply restrictions on their domains. $y=2\ \$ on $\ [0,1)$ and $\ [2,3)$ $y=0\ \$ on $\ [1,2)$ and $\ [3,4]$