## University Calculus: Early Transcendentals (3rd Edition)

Increasing: $(-\infty,\infty)$ Decreasing: nowhere Graph is symmetric with respect to the origin.
$\mathrm{First\:Part:}\:\:$ According to the definitions: A function $\ f\$ defined on an interval is increasing on $\ (a, b)\$ if for every $\ x_1, x_2\$ $\in$ $(a, b)$ $\ x_1\le x_2\$ implies that $\ f(x_1)\le f(x_2).\$ A function $\ f\$ defined on an interval is decreasing on $\ (a, b)\$ if for every $\ x_1, x_2\$ $\in$ $(a, b)$ $\ x_1\le x_2\$ implies that $\ f(x_1)\ge f(x_2).\$ First of all create a table with few points to sketch the graph. $\quad \mathrm{See\:the\:table\:and\:graph\:above.}$ $\mathrm{Second\:Part:}\:\:$ Graph is symmetric with respect to the origin. $\mathrm{Third\:Part:}\:\:$ The graph of the given function $\ y=\frac{x^3}{8}\$ is increasing on $\ (-\infty,\infty).$