Answer
We know from the first fundamental theorem of calculus if $h(x)$ is a continuous, real-valued function $\forall x\epsilon [a,b]$ and if $H(x)$ is given by $H(x)=\int_{a}^{x}h(y)dy$ then $H^{\prime}(x)=\frac{d}{dx}\int_{a}^{x}h(y)dy=h(x)$. Using this we can get our solution.
Work Step by Step
The answer: