Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 7: Transcendental Functions - Section 7.4 - Exponential Change and Separable Differential Equations - Exercises 7.4 - Page 400: 18

Answer

$\frac{e^{2y}}{2}$ = $e^{x}+C$

Work Step by Step

$\frac{dy}{dx}$ = $\frac{e^{2x-y}}{e^{x+y}}$ $\frac{dy}{dx}$ = ${e^{2x-y-x-y}}$ $\frac{dy}{dx}$ = ${e^{x-2y}}$ $e^{2y}dy$ = $e^{x}dx$ $\int(e^{2y})dy$ = $\int(e^{x})dx$ $\frac{e^{2y}}{2}$ = $e^{x}+C$
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