Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 7: Transcendental Functions - Section 7.4 - Exponential Change and Separable Differential Equations - Exercises 7.4 - Page 400: 12

Answer

$e^y-x^3=c$

Work Step by Step

As we are given that $\dfrac{dy}{dx}=3x^2 e^{-y}$ Re-arrange the given equation as follows: $\dfrac{dy}{dx}=\dfrac{(3x^2)}{e^y}$ This implies that $(e^y) dy=(3x^2) dx$ Now take the help of integration. Then $\int (e^y) dy=\int (3x^2) dx$ Use formula: $\int x^n dx=\dfrac{x^{n+1}}{n+1}+c$ $\int (e^y) dy=\int (3x^2) dx \implies e^y=\dfrac{3x^{2+1}}{2+1}+c$ Hence, $\dfrac{3x^{3}}{3}+c =e^y\implies e^y-x^3=c$
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