Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 4: Applications of Derivatives - Section 4.5 - Applied Optimization - Exercises 4.5 - Page 227: 63

Answer

Parallel to each other.

Work Step by Step

Step 1. Letting $h(x)=f(x)-g(x)$, since point $c$ gives the maximum of $h(x)$, we have $h'(c)=0$ Step 2. With $h'(x)=f'(x)-g'(x)=$, we have $h'(c)=f'(c)-g'(c)=0$; thus $f'(c)=g'(c)$ Step 3. By definition, $f'(c)$ represents the slope of the tangent line to $f(x)$ at point $c$, and the same for $g'(c)$. Thus, we conclude that the tangents to the two curves at $c$ are parallel to each other.
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