Answer
$(\dfrac{-1}{\pi}) \cot (\pi s)+c$
Work Step by Step
Use formula $\int x^{a} dx=\dfrac{x^{a+1}}{n+1}+c$
where $c$ is a constant of proportionality.
As we know that $\int \csc^2 x =-\cot t+C$
Plug $\pi s =a $ and $\pi ds=da$
$\int \csc^2 a (\dfrac{1}{\pi}) da=(\dfrac{1}{\pi}) \int \csc^2 (a) da$
or, $(\dfrac{1}{\pi}) \int \csc^2 (a) da=(\dfrac{-1}{\pi}) \cot (a)+c$
Hence, $(\dfrac{-1}{\pi}) \cot (a)+c=(\dfrac{-1}{\pi}) \cot (\pi s)+c$
