Answer
$-(\dfrac{5}{8}) (2-x)^{(8/5)}+c$
Work Step by Step
Since, we know $\int x^{a} dx=\dfrac{x^{a+1}}{n+1}+c$
where $c$ is a constant of proportionality.
Plug $2-x=a$ and $dx =-da$
$a^{3/5} da=[\dfrac{a^{3/5+1}}{3/5+1}]+c$
or, $[\dfrac{a^{3/5+1}}{\frac{3}{5}+1}]+c=-(\dfrac{5}{8}) [a^{(8/5)}]+c$
Hence, $-(\dfrac{5}{8}) [a^{(8/5)}]+c=-(\dfrac{5}{8}) (2-x)^{(8/5)}+c$
