Answer
$10 \tan (\dfrac{s}{10})+c$
Work Step by Step
Use formula $\int x^{a} dx=\dfrac{x^{a+1}}{n+1}+c$
where $c$ is a constant of proportionality.
Apply formula $\int \sec^2 x =\tan x$
$\int \sec^2 (\dfrac{s}{10}) ds=\dfrac{1}{\frac{1}{10}} \tan (\dfrac{s}{10})+c$
Hence, $\int \sec^2 (\dfrac{s}{10}) ds=10 \tan (\dfrac{s}{10})+c$
