Answer
$y$ = $-4x+1$
Work Step by Step
$y$ = $(\frac{x-1}{x+1})^{2}$
$y(0)$ = $(\frac{0-1}{0+1})^{2}$ = $1$
$y'$ = $2(\frac{x-1}{x+1})$[$\frac{(x+1)(1)-(x-1)(1)}{(x+1)^{2}}$] = $\frac{4(x-1)}{(x+1)^{3}}$
$y'(0)$ = $\frac{4(0-1)}{(0+1)^{3}}$ =$-4$
$y'$ = slope = m
$y-y_{1}$ = $m(x-x_{1})$
$y-1$ = $-4(x-0)$
$y$ = $-4x+1$
