Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.6 - The Chain Rule - Exercises 3.6 - Page 149: 38

Answer

$(27x^4-18x^3+6x^2+18x-6)e^{x^3}$

Work Step by Step

$ y=(9x^2-6x+2)e^{x^3}$ Apply the chain rule: $y'=(9x^2-6x+2).e^{x^3}(3x^2)+(18x-6).e^{x^3}$ =$(27x^4-18x^3+6x^2+18x-6)e^{x^3}$
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