Answer
a. $2$
b. $ y=2x-7$
Work Step by Step
Given $ y=x^2-2x-3, P(2,-3)$
a. slope=$\frac{(2+h)^2-2(2+h)-2^2+2\times2}{h}=\frac{4h+h^2-2h}{h}=2+h=2$ (let $h$ approach zero)
b. tangent line: $ y+3=2(x-2)$, which leads to $ y=2x-7$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 2: Limits and Continuity - Section 2.1 - Rates of Change and Tangents to Curves - Exercises 2.1 - Page 46: 9
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
