Answer
a. $-2$
b. $ y=-2x-1$
Work Step by Step
Given $ y=x^2-4x, P(1,-3)$
a. slope=$\frac{(1+h)^2-4(1+h)-1^2+4\times1}{h}=\frac{2h+h^2-4h}{h}=-2+h=-2$ (as $h$ approach zero)
b. tangent line: $ y+3=-2(x-1)$, which gives $ y=-2x-1$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 2: Limits and Continuity - Section 2.1 - Rates of Change and Tangents to Curves - Exercises 2.1 - Page 46: 10
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